(1/n+3)+(5/n^2-9)=(2/n-3

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Solution for (1/n+3)+(5/n^2-9)=(2/n-3 equation: 



(1/n+3)+(5/n^2-9)=(2/n-3

We move all terms to the left:

(1/n+3)+(5/n^2-9)-((2/n-3)=0



Domain of the equation: n+3)!=0

n∈R





Domain of the equation: n^2-9)!=0

n∈R





Domain of the equation: n-3)!=0

n∈R



We get rid of parentheses

1/n+5/n^2-((2/n-3)+3-9=0

We calculate fractions

We do not support enpression: n^4

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